Homework Template for Chemical Engineers (UCR)
Forfatter
Stuar Tencio
Last Updated
2 years ago
License
Creative Commons CC BY 4.0
Resumé
This template aims to help the student to better organize any evaluation (UCR, 2021).
This template aims to help the student to better organize any evaluation (UCR, 2021).
\documentclass[11pt,letterpaper]{article}
\usepackage[lmargin=0.75in,rmargin=0.75in,tmargin=0.75in,bmargin=0.5in]{geometry}
% -------------------
% Packages
% -------------------
\usepackage{
amsmath, % Math Environments
amssymb, % Extended Symbols
enumerate, % Enumerate Environments
graphicx, % Include Images
lastpage, % Reference Lastpage
multicol, % Use Multi-columns
multirow % Use Multi-rows
}
\usepackage[framemethod=TikZ]{mdframed}
\usepackage{tikz, tabularx}
\usepackage{graphics}
\newcolumntype{W}{>{\centering\arraybackslash}X}%Para agilizar las columnas.
% -------------------
% Font
% -------------------
\usepackage[T1]{fontenc}
\usepackage{charter}
% -------------------
% Commands
% -------------------
\newcommand{\homework}[2]{\noindent\textbf{Nombre completo: }\makebox[3in]{\hrulefill} \hfill \textbf{IQ 0312} \\ \textbf{Fecha de entrega: #2} \hfill \textbf{Simulacro #1}\\}
\newcommand{\prob}{\noindent\textbf{Problema. }}
\newcounter{problema}
\newcommand{\problem}{
\stepcounter{problema}%
\noindent \textbf{Problema \theproblem. }%
}
\newcommand{\pointproblem}[1]{
\stepcounter{problema}%
\noindent \textbf{Problema \theproblem.} (#1 points)\,%
}
\newcommand{\pspace}{\par\vspace{\baselineskip}}
\newcommand{\ds}{\displaystyle}
% -------------------
% Theorem Environment
% -------------------
\mdfdefinestyle{theoremstyle}{%
frametitlerule=true,
roundcorner=5pt,
linecolor=black,
outerlinewidth=0.5pt,
middlelinewidth=0.5pt
}
\mdtheorem[style=theoremstyle]{exercise}{\textbf{Problema}}
% -------------------
% Header & Footer
% -------------------
\usepackage{fancyhdr}
\fancypagestyle{pages}{
%Headers
\fancyhead[L]{}
\fancyhead[C]{}
\fancyhead[R]{}
\renewcommand{\headrulewidth}{0pt}
%Footers
\fancyfoot[L]{}
\fancyfoot[C]{}
\fancyfoot[R]{\thepage \,de \pageref{LastPage}}
\renewcommand{\footrulewidth}{0.0pt}
}
\headheight=0pt
\footskip=14pt
\pagestyle{pages}
% -------------------
% Content
% -------------------
\begin{document}
\homework{\#}{MM/DD}
% Question 1
\begin{exercise}
This problem has several parts:
\begin{enumerate}[(a)]
\item The first part.
\item The second part.
\item The third part.
\end{enumerate}
\end{exercise}
% Question 2
\begin{exercise}
For each of the following below, determine which option is correct.
\begin{enumerate}[(i)]
\item
\begin{tabular}{p{3cm}p{3cm}p{3cm}p{3cm}}
a) $2 \cdot 2= 4$ & b) $x^3= x \cdot x$ & c) $\sin x = \cos x$ & d) $\sin x^2= \sin^2 x$
\end{tabular}
\item
\begin{tabular}{p{3cm}p{3cm}p{3cm}p{3cm}}
a) $2 \cdot 2= 4$ & b) $x^3= x \cdot x$ & c) $\sin x = \cos x$ & d) $\sin x^2= \sin^2 x$
\end{tabular}
\end{enumerate}
\end{exercise}
% Question 3
\begin{exercise}
Compute the following integral:
\[
\int e^{-x^2} \;dx
\] \vspace{6mm}
Referencias ecuaciones se vuelve más sencillo al usar el comando
\begin{verbatim}
\ref{eqn:Nombre de la etiqueta}
\end{verbatim}
Tal como se muestra aquí, [\ref{eqn:Reaction_A}] en [\ref{eqn:Reaction_B}]:
\begin{eqnarray*}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray*}
\tikzset{every picture/.style={line width=0.75pt}} %set default line width to 0.75pt
\begin{tikzpicture}[x=0.75pt,y=0.75pt,yscale=-1,xscale=1]
%uncomment if require: \path (0,300); %set diagram left start at 0, and has height of 300
%Straight Lines [id:da06479745589279151]
\draw (100,129) -- (100,40) ;
\draw [shift={(100,38)}, rotate = 450] [color={rgb, 255:red, 0; green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) .. (10.93,3.29) ;
%Straight Lines [id:da4488309641620518]
\draw (100,129) -- (281,129) ;
\draw [shift={(283,129)}, rotate = 180] [color={rgb, 255:red, 0; green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) .. (10.93,3.29) ;
%Straight Lines [id:da745498636001752]
\draw (100,129) -- (169.76,106.33) -- (220,90) ;
%Shape: Circle [id:dp8575930364347657]
\draw (136,82) .. controls (136,68.19) and (147.19,57) .. (161,57) .. controls (174.81,57) and (186,68.19) .. (186,82) .. controls (186,95.81) and (174.81,107) .. (161,107) .. controls (147.19,107) and (136,95.81) .. (136,82) -- cycle ;
%Straight Lines [id:da894572965309491]
\draw [color={rgb, 255:red, 126; green, 63; blue, 23 } ,draw opacity=1 ] (169.76,163) -- (169.76,108.33) ;
\draw [shift={(169.76,106.33)}, rotate = 450] [color={rgb, 255:red, 126; green, 63; blue, 23 } ,draw opacity=1 ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) .. (10.93,3.29) ;
\end{tikzpicture}
\end{exercise}
\newpage
Otra forma de poder ubicar varios balances puede ser usando tablas.
\begin{table}[!hbt]
\centering
\begin{tabularx}{\columnwidth}{*{3}{W}}
\textbf{Balance momentos}&\textbf{Balance fuerza x}&\textbf{Balance fuerza y}\\
\begin{eqnarray}\label{eqn:Reaction_A}
\nonumber x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\ \nonumber
xy+y^2 & = & 2x
\end{eqnarray} & \begin{eqnarray}\label{eqn:Reaction_B}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray} & \begin{eqnarray}\label{eqn:Reaction_C}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray}\\
\end{tabularx}
\label{tab:my_label}
\end{table}
\end{document}