This template aims to help the student to better organize any evaluation (UCR, 2021).
\begin
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\documentclass[11pt,letterpaper]{article}
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% Packages
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\usepackage{
amsmath, % Math Environments
amssymb, % Extended Symbols
enumerate, % Enumerate Environments
graphicx, % Include Images
lastpage, % Reference Lastpage
multicol, % Use Multi-columns
multirow % Use Multi-rows
}
\usepackage[framemethod=TikZ]{mdframed}
\usepackage{tikz, tabularx}
\usepackage{graphics}
\newcolumntype{W}{>{\centering\arraybackslash}X}%Para agilizar las columnas.
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% Font
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\usepackage[T1]{fontenc}
\usepackage{charter}
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% Commands
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\newcommand{\homework}[2]{\noindent\textbf{Nombre completo: }\makebox[3in]{\hrulefill} \hfill \textbf{IQ 0312} \\ \textbf{Fecha de entrega: #2} \hfill \textbf{Simulacro #1}\\}
\newcommand{\prob}{\noindent\textbf{Problema. }}
\newcounter{problema}
\newcommand{\problem}{
\stepcounter{problema}%
\noindent \textbf{Problema \theproblem. }%
}
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\stepcounter{problema}%
\noindent \textbf{Problema \theproblem.} (#1 points)\,%
}
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\newcommand{\ds}{\displaystyle}
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% Theorem Environment
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\mdtheorem[style=theoremstyle]{exercise}{\textbf{Problema}}
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% Content
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\begin{document}
\homework{\#}{MM/DD}
% Question 1
\begin{exercise}
This problem has several parts:
\begin{enumerate}[(a)]
\item The first part.
\item The second part.
\item The third part.
\end{enumerate}
\end{exercise}
% Question 2
\begin{exercise}
For each of the following below, determine which option is correct.
\begin{enumerate}[(i)]
\item
\begin{tabular}{p{3cm}p{3cm}p{3cm}p{3cm}}
a) $2 \cdot 2= 4$ & b) $x^3= x \cdot x$ & c) $\sin x = \cos x$ & d) $\sin x^2= \sin^2 x$
\end{tabular}
\item
\begin{tabular}{p{3cm}p{3cm}p{3cm}p{3cm}}
a) $2 \cdot 2= 4$ & b) $x^3= x \cdot x$ & c) $\sin x = \cos x$ & d) $\sin x^2= \sin^2 x$
\end{tabular}
\end{enumerate}
\end{exercise}
% Question 3
\begin{exercise}
Compute the following integral:
\[
\int e^{-x^2} \;dx
\] \vspace{6mm}
Referencias ecuaciones se vuelve más sencillo al usar el comando
\begin{verbatim}
\ref{eqn:Nombre de la etiqueta}
\end{verbatim}
Tal como se muestra aquí, [\ref{eqn:Reaction_A}] en [\ref{eqn:Reaction_B}]:
\begin{eqnarray*}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray*}
\tikzset{every picture/.style={line width=0.75pt}} %set default line width to 0.75pt
\begin{tikzpicture}[x=0.75pt,y=0.75pt,yscale=-1,xscale=1]
%uncomment if require: \path (0,300); %set diagram left start at 0, and has height of 300
%Straight Lines [id:da06479745589279151]
\draw (100,129) -- (100,40) ;
\draw [shift={(100,38)}, rotate = 450] [color={rgb, 255:red, 0; green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) .. (10.93,3.29) ;
%Straight Lines [id:da4488309641620518]
\draw (100,129) -- (281,129) ;
\draw [shift={(283,129)}, rotate = 180] [color={rgb, 255:red, 0; green, 0; blue, 0 } ][line width=0.75] (10.93,-3.29) .. controls (6.95,-1.4) and (3.31,-0.3) .. (0,0) .. controls (3.31,0.3) and (6.95,1.4) .. (10.93,3.29) ;
%Straight Lines [id:da745498636001752]
\draw (100,129) -- (169.76,106.33) -- (220,90) ;
%Shape: Circle [id:dp8575930364347657]
\draw (136,82) .. controls (136,68.19) and (147.19,57) .. (161,57) .. controls (174.81,57) and (186,68.19) .. (186,82) .. controls (186,95.81) and (174.81,107) .. (161,107) .. controls (147.19,107) and (136,95.81) .. (136,82) -- cycle ;
%Straight Lines [id:da894572965309491]
\draw [color={rgb, 255:red, 126; green, 63; blue, 23 } ,draw opacity=1 ] (169.76,163) -- (169.76,108.33) ;
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\end{tikzpicture}
\end{exercise}
\newpage
Otra forma de poder ubicar varios balances puede ser usando tablas.
\begin{table}[!hbt]
\centering
\begin{tabularx}{\columnwidth}{*{3}{W}}
\textbf{Balance momentos}&\textbf{Balance fuerza x}&\textbf{Balance fuerza y}\\
\begin{eqnarray}\label{eqn:Reaction_A}
\nonumber x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\ \nonumber
xy+y^2 & = & 2x
\end{eqnarray} & \begin{eqnarray}\label{eqn:Reaction_B}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray} & \begin{eqnarray}\label{eqn:Reaction_C}
x+y & = & \frac{2x}{y} \\
y(x+y) & = & 2x \\
xy+y^2 & = & 2x
\end{eqnarray}\\
\end{tabularx}
\label{tab:my_label}
\end{table}
\end{document}